2x^2+12.5x+18=0

Solution for 2x^2+12.5x+18=0 equation:

2x^2+12.5x+18=0

a = 2; b = 12.5; c = +18;
Δ = b2-4ac
Δ = 12.52-4·2·18
Δ = 12.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12.5)-\sqrt{12.25}}{2*2}=\frac{-12.5-\sqrt{12.25}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12.5)+\sqrt{12.25}}{2*2}=\frac{-12.5+\sqrt{12.25}}{4}
$